2020-02-10 javascript

Searching inside of an array of objects - Javascript

One of my favorite methods from the Arrays object, is the .filter() method. It allows javascript programs to search for an element inside of an array. What I like the most about this method, is that developers have the flexibility of searching an item inside of an array of any data structure.

On this blog post, I will focus on:

  • Searching/filtering items inside of an array of objects
  • Write a wrapper function that allows javascript programs to search/filter items inside of an of array of objects

The syntax of filter()

The .filter() method receives a function as a callback or argument. This function has one mandatory argument which represents each item in the array. The callback function needs to return either true or false by testing the existence or non-existence of each array’s element.

Searching/filtering an element of type Number

const x = [0, 1, 20, 4, 5];

console.log(x.filter((item) => item === 4));

// 4

Searching for objects

To search for an object inside of an array, it’s important to know the object structure and then write a callback function that fits that.


const listOfNames = [
    name: "Firmino",
    age: 23,
    name: "Gonçalves",
    age: 19,
    name: "Changani",
    age: 8,
    name: "Nelson",
    age: 67,
    name: "Mandela",
    age: 34,

const result = listOfNames.filter((item) => {
  return item.name.search(new RegExp("MANDELA", "i")) >= 0;


The code above is little bit more complex than the first example, but the essence is exactly the same:

  • An array listOfNames that contains several objects, each with two properties: name and age
  • The result of the filter operation will be assigned to the result constant
  • Inside the callback function, I am using the .search() method on item.name to search for the string MANDELA. .search() is case sensitive, it tries to look for the exact same string. To go around this, I am passing a regular expression with the option i for case insensitive, instead of plain string
  • .search will return -1 if it couldn’t match the string, or it will return a positive integer starting from O if the string was matched

A general solution

The code above works, but I decided to work on a general approach that would also allow programs to set the object property to be used as a search parameter, and also support filtering/searching on properties with Number as data type.

 * search: It return an array of elements that match
 * the search condition
 * @param {Array} arr
 * @param {String} prop
 * @param {String/Number} param
 * @returns {Array}
function search(arr = [], prop, param) {
  const searchParam = new RegExp(param, "i");
  return arr.filter((item) => {
    return new String(item[prop]).search(searchParam) >= 0;
  • The search function receives 3 arguments: arr an Array of objects, prop the property to be used as search/filter parameter, and param which represents the actual value we expect the .search() to match
  • To improve the readability, I assigned the regular expression declaration to the searchParam constant
  • And to support the Number data type, I decided to wrap item[prop] inside of new String(). This means that each property value would be converted to a String
  • And last, since the function doesn’t know which object property would be used as a search parameter, I decided to access the property by using a square brackets and pass the prop value like thisitem[prop]

This function could be improved, with things like parameter validation, support for nested objects and so on, but for the sake of simplicity, I decided to leave it just like it is right now.